12(x^2-8)=3x(4x+1)

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Solution for 12(x^2-8)=3x(4x+1) equation: 



12(x^2-8)=3x(4x+1)

We move all terms to the left:

12(x^2-8)-(3x(4x+1))=0

We multiply parentheses

12x^2-(3x(4x+1))-96=0



We calculate terms in parentheses: -(3x(4x+1)), so:

3x(4x+1)

We multiply parentheses

12x^2+3x

Back to the equation:

-(12x^2+3x)



We get rid of parentheses

12x^2-12x^2-3x-96=0

We add all the numbers together, and all the variables

-3x-96=0

We move all terms containing x to the left, all other terms to the right

-3x=96

x=96/-3

x=-32

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